Welcome to my article 1/x+1+2/x+2=4/x+4. This question is taken from the simplification lesson.

The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.

For complete information on how to solve this question 1/x+1+2/x+2=4/x+4, read and understand it carefully till the end.

## Let us know how to solve this question 1/x+1+2/x+2=4/x+4.

First write the question on the page of the notebook

\displaystyle \frac{1}{x}+1+\frac{2}{x}+2=\frac{4}{x}+4In this article, first of all, let’s keep the variable amount together and the constant amount together. This is how they solve.

\displaystyle \frac{1}{x}+\frac{2}{x}+1+2=\frac{4}{x}+4We see that their denominators are equal, then add their numerators.

\displaystyle \frac{3}{x}+3=\frac{4}{x}+4Note the sites also change. When you change sides, the symbol also changes. Do it this way.

\displaystyle \frac{3}{x}-\frac{4}{x}=4-3 \displaystyle \frac{{3-4}}{x}=4-3 \displaystyle \frac{{-1}}{x}=1 \displaystyle -1=1\text{x}x-1=x

**or, x=-1 Answer**

### To see other examples like this see

## 2/x+6+7/x+9?x=5/x-2/x

To solve such questions, first of all put the variable amount terms together as follows and keep the constant amount terms together.

\displaystyle \frac{2}{x}+\frac{7}{x}+\frac{9}{x}-\frac{5}{x}+\frac{2}{x}=-6Since the denominators are equal, add the numerators together in the following way.

\displaystyle \frac{{2+7+9-5+2}}{x}=-6 \displaystyle \frac{{20-5}}{x}=-6Change sides.

\displaystyle \frac{{15}}{x}+6=0 \displaystyle \frac{{15+6x}}{x}=0Since multiplying 0 by any number gives 0. so 0xX = 0

\displaystyle 15+6x=0 \displaystyle 6x=-15 \displaystyle x=-\frac{{15}}{6}-15 /6 can also be written as 5×3 /2×3. If there is a similar number from the bottom up and down, then remove it.

\displaystyle x=\frac{{-5}}{2}AnswerHow to solve 1/x+1+2/x+2=4/x+4 ? This article has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.

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