# How to solve 1/x+1+2/x+2=4/x+4 ?

Welcome to my article 1/x+1+2/x+2=4/x+4. This question is taken from the simplification lesson.
The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
For complete information on how to solve this question 1/x+1+2/x+2=4/x+4, read and understand it carefully till the end.

## Let us know how to solve this question 1/x+1+2/x+2=4/x+4.

First write the question on the page of the notebook

\displaystyle \frac{1}{x}+1+\frac{2}{x}+2=\frac{4}{x}+4

In this article, first of all, let’s keep the variable amount together and the constant amount together. This is how they solve.

\displaystyle \frac{1}{x}+\frac{2}{x}+1+2=\frac{4}{x}+4

We see that their denominators are equal, then add their numerators.

\displaystyle \frac{3}{x}+3=\frac{4}{x}+4

Note the sites also change. When you change sides, the symbol also changes. Do it this way.

\displaystyle \frac{3}{x}-\frac{4}{x}=4-3

\displaystyle \frac{{3-4}}{x}=4-3

\displaystyle \frac{{-1}}{x}=1

\displaystyle -1=1\text{x}x

-1=x

## 2/x+6+7/x+9?x=5/x-2/x

To solve such questions, first of all put the variable amount terms together as follows and keep the constant amount terms together.

\displaystyle \frac{2}{x}+\frac{7}{x}+\frac{9}{x}-\frac{5}{x}+\frac{2}{x}=-6

Since the denominators are equal, add the numerators together in the following way.

\displaystyle \frac{{2+7+9-5+2}}{x}=-6

\displaystyle \frac{{20-5}}{x}=-6

Change sides.

\displaystyle \frac{{15}}{x}+6=0

\displaystyle \frac{{15+6x}}{x}=0

Since multiplying 0 by any number gives 0. so 0xX = 0

\displaystyle 15+6x=0

\displaystyle 6x=-15

\displaystyle x=-\frac{{15}}{6}

-15 /6 can also be written as 5×3 /2×3. If there is a similar number from the bottom up and down, then remove it.