# How to solve 1/x+1+2/x+2=5/x+4?

hello friends,
Welcome to my article 1/x+1+2/x+2=5/x+4.
This article has been taken from the simplification lesson, in this article we have been told to simplify with the action of addition, subtraction, multiplication, division and fractions.

The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
For complete information on how to solve this question 1/x+1+2/x+2=5/x+4, read and understand it carefully till the end.

First of all we should write the article on the page of the notebook.

## 1/x+1+2/x+2=5/x+4

Let’s solve it by placing it up and down,

\displaystyle \frac{1}{x}+1+\frac{2}{x}+2=\frac{5}{x}+4

First of all, we need to understand such questions and solve them in a simple way by keeping the terms of variable amount with variable amount and the terms of constant amount with constant amount.

\displaystyle \frac{1}{x}+\frac{2}{x}+1+2=\frac{5}{x}+4

Now if the denominators are equal, then add their numerators together.

\displaystyle \frac{{1+2}}{x}+3=\frac{5}{x}+4

\displaystyle \frac{3}{x}+3=\frac{5}{x}+4

\displaystyle \frac{3}{x}-\frac{5}{x}=4-3

\displaystyle \frac{{3-5}}{x}=1

\displaystyle \frac{{-2}}{x}=1

\displaystyle -2=x

This article has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.

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Similarly, as an example, see / understand the solution of the question –

how to solve 18/x-7/x+6-2/x-9=3/x+2?

First of all we should write the article on the page of the notebook.
18/x-7/x+6-2/x-9=3/x+2
Let’s solve it by placing it up and down,

\displaystyle \frac{{18}}{x}-\frac{7}{x}+6-\frac{2}{x}-9=\frac{3}{x}+2

First of all, we need to understand such questions and solve them in a simple way by keeping the terms of variable amount with variable amount and the terms of constant amount with constant amount.

\displaystyle \frac{{18}}{x}-\frac{7}{x}-\frac{2}{x}+6-9=\frac{3}{x}+2

\displaystyle \frac{{18-7-2}}{x}-3=\frac{3}{x}+2

\displaystyle \frac{9}{x}-3=\frac{3}{x}+2

Now let’s transpose –

\displaystyle \frac{9}{x}-\frac{3}{x}=3+2

Now if the denominators are equal, then add their numerators together.

\displaystyle \frac{{9-3}}{x}=5

\displaystyle \frac{6}{x}=5

\displaystyle 6=5x

\displaystyle \frac{6}{5}=x

or,

This article has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.

Note: If you have any such question, then definitely send it by writing in our comment box to get the answer.

Similarly, as an example, see / understand the solution of the question

how to solve ,3/x-4+6/x+3=13+7/x+6?

First of all we should write the article on the page of the notebook.
3/x-4+6/x+3=13+7/x+6
Let’s solve it by placing it up and down,

\displaystyle \frac{3}{x}-4+\frac{6}{x}+3=13+\frac{7}{x}+6

First of all, we need to understand such questions and solve them in a simple way by keeping the terms of variable amount with variable amount and the terms of constant amount with constant amount.

\displaystyle \frac{3}{x}+\frac{6}{x}-4+3=\frac{7}{x}+6+13

\displaystyle \frac{{3+6}}{x}-1=\frac{7}{x}+19

\displaystyle \frac{9}{x}-1=\frac{7}{x}+19

Now let’s transpose –

\displaystyle \frac{9}{x}-\frac{7}{x}=1+19

Now if the denominators are equal, then add their numerators together.

\displaystyle \frac{{9+(-7)}}{x}=1+19

\displaystyle \frac{{9-7}}{x}=20

\displaystyle \frac{2}{x}=20

\displaystyle 2=20x

\displaystyle \frac{2}{{20}}=x

\displaystyle \frac{1}{{10}}\text{x }\frac{2}{2}=x

\displaystyle \frac{1}{{10}}=x

or,