# How to Solve 1/X+1+2/X+2+7/X+5?

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Welcome to my article 1/x+1+2/x+2=7/x+5.
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First of all we should write the article on the page of the notebook.

## 1/x+1+2/x+2=7/x+5

Let’s solve it by placing it up and down,

\displaystyle \frac{1}{{x-1}}+\frac{2}{{x+2}}=\frac{7}{{x+5}}

We see that there is a sky for the positions of both the sides.
So we can easily solve by multiplying (x + 1 ),(x +2),(x +5) with both sides,

\displaystyle (x+2)(x+5)+2(x+1)(x+5)=7(x+1)(x+2)

After this we will get this –

\displaystyle {{x}^{2}}+7x+10+2{{x}^{2}}+12x+10=7{{x}^{2}}+21x+14

\displaystyle 3{{x}^{2}}+19x+20=7{{x}^{2}}+21x+14

on transposition,

\displaystyle 3{{x}^{2}}-7{{x}^{2}}+19x-21x+20-14=0

\displaystyle -4{{x}^{2}}-2x+6=0

On dividing both the sides by -2,

\displaystyle 2{{x}^{2}}+x-3=0

We find that this is the term of the quadratic equation, so we divide it by dividing the middle term,

\displaystyle 2{{x}^{2}}+3x-2x=0

\displaystyle x(2x+3)-1(2x+3)=0

\displaystyle (2x+3)(x-1)=0

On finding the value of X –

If ,
2x +3=0
So ,x = -3/2
and x -1=0 ,
So ,x =1
Similarly,

How to Solve 1/X+1+2/X+2+7/X+5? This article has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.

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## HOW TO SOLVE 2/3+X+1/3+X+7/X+3?

Let’s solve this example according to the solution of the above question,

First of all we should write the article on the page of the notebook.

2/3+X+1/3+X+7/X+3

Let’s solve it by placing it up and down,

\displaystyle \frac{2}{{3+x}}+\frac{1}{{3+x}}+\frac{7}{{x+3}}

On writing every single one of this question –

Each denominator of this question can be written as –

\displaystyle \frac{2}{{x+3}}+\frac{1}{{x+3}}+\frac{7}{{x+3}}

when you write like this,
So we can easily solve such question;
We already know that when the denominators of terms are equal, their numerators are added together,

\displaystyle \frac{{2+1+7}}{{x+3}}

\displystyle \frac{{10}}{{x+3}}

Let 10/x + 3 = 1 Then,

\displaystyle \frac{{10}}{{x+3}}=1

on transposition,

\displaystyle \frac{{10}}{1}=1\text{x}(x+3)

\displaystyle 10=x+3

\displaystyle 10-3=x

\displaystyle 7=x