# How to solve 2/4+6/4+6/2-3/2=x-5/6

Welcome to my article How to solve 2/4+6/4+6/2-3/2=x-5/6. This question is taken from the simplification lesson.
The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
For complete information on how to solve this question How to solve 2/4+6/4+6/2-3/2=x-5/6, read and understand it carefully till the end.

Let us know how to solve this question How to solve 2/4+6/4+6/2-3/2=x-5/6

First write the question on the page of the notebook.

## How to solve 2/4+6/4+6/2-3/2=x-5/6

First of all write like this,

\displaystyle \text{ }\frac{2}{4}+\frac{6}{4}+\frac{6}{2}-\frac{3}{2}=x-\frac{5}{6}

\displaystyle \text{ }\frac{{2\times 1}}{{2\times 2}}+\frac{6}{4}+\frac{6}{2}-\frac{3}{2}=x-\frac{5}{6}

\displaystyle \text{ }\frac{1}{2}+\frac{6}{4}+\frac{6}{2}-\frac{3}{2}=x-\frac{5}{6}

\displaystyle \text{ }\frac{1}{2}+\frac{{3\times 2}}{{2\times 2}}+\frac{6}{2}-\frac{3}{2}=x-\frac{5}{6}

\displaystyle \text{ }\frac{1}{2}+\frac{3}{2}+\frac{6}{2}-\frac{3}{2}=x-\frac{5}{6}

If all the fractions have the same denominator, then their numerators are added together.

\displaystyle \text{ }\frac{{1+3+6+(-3)}}{2}=x-\frac{5}{6}

\displaystyle \text{ }\frac{{10+(-3)}}{2}=x-\frac{5}{6}

\displaystyle \text{ }\frac{{10-3}}{2}=x-\frac{5}{6}

\displaystyle \text{ }\frac{7}{2}=x-\frac{5}{6}

on transposition,

\displaystyle \text{ }\frac{7}{2}+\frac{5}{6}=x

\displaystyle \text{ }\frac{{7\times 3}}{{2\times 3}}+\frac{5}{6}=x

\displaystyle \text{ }\frac{{21}}{6}+\frac{5}{6}=x

\displaystyle \text{ }\frac{{21+5}}{6}=x

\displaystyle \text{ }\frac{{26}}{6}=x

\displaystyle \text{ }\frac{{2\times 13}}{{2\times 3}}=x

\displaystyle \text{ }\frac{{13}}{3}=x

\displaystyle \text{ 4}\frac{1}{3}=x

or,

\displaystyle \text{ }x=\text{4}\frac{1}{3}