Welcome to my article **How to solve 2×3-9×2+4x-5**. This question is taken from the simplification lesson.

The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.

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**How to solve 2×3-9×2+4x-5**

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\displaystyle \mathbf{2}{{\mathbf{x}}^{3}}-\mathbf{9}{{\mathbf{x}}^{2}}+\mathbf{4x}-\mathbf{5} \displaystyle \mathbf{2}{{\mathbf{x}}^{3}}+10{{\mathbf{x}}^{2}}-{{\mathbf{x}}^{2}}+\mathbf{4x}-\mathbf{5} \displaystyle \mathbf{2}{{\mathbf{x}}^{3}}-{{\mathbf{x}}^{2}}+\mathbf{4x}+10{{\mathbf{x}}^{2}}-\mathbf{5} \displaystyle x(2{{x}^{2}}-x+4)+10{{x}^{2}}-\mathbf{5} \displaystyle x(2{{x}^{2}}-x+4)+5(2{{x}^{2}}-1)** \displaystyle (2{{x}^{2}}-x+4)(2{{x}^{2}}-1)(x+5) [Answer]**

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