# How to solve 3^2 + 9^2 / 3^2-6x/2 =0

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## How to solve 3^2 + 9^2 / 3^2-6x/2 =0

We will solve this question in a simple way as follows and write this type ,

\displaystyle {{3}^{2}}+\frac{{{{9}^{2}}}}{{{{3}^{2}}}}-\frac{{6x}}{2}=0

\displaystyle {{3}^{2}}+{{\left( {\frac{9}{3}} \right)}^{2}}-\frac{2}{2}\times 3x=0

\displaystyle {{3}^{2}}+{{\left( {\frac{3}{3}\times 3} \right)}^{2}}-3x=0

\displaystyle {{3}^{2}}+{{\left( 3 \right)}^{2}}-3x=0

\$latex \displaystyle 3\times 3+3\times 3-3x=0[/latex]

\displaystyle 9+9-3x=0

\displaystyle 18-3x=0

\displaystyle -3x=-18

\displaystyle x=\frac{{-18}}{{-3}}

\displaystyle x=\frac{{18}}{3}

\displaystyle x=\frac{3}{3}\times 6

\displaystyle x=6