# How to solve 4-8/2*(4/6)+9/8

Welcome to my article How to solve 4-8/2*(4/6)+9/8. This question is taken from the simplification lesson.
The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
For complete information on how to solve this question How to solve 4-8/2*(4/6)+9/8, read and understand it carefully till the end.

Let us know how to solve this question How to solve 4-8/2*(4/6)+9/8.

First write the question on the page of the notebook.

## How to solve 4-8/2*(4/6)+9/8

First of all write it like this,

\displaystyle 4-\frac{8}{2}\times (\frac{4}{6})+\frac{9}{8}

\displaystyle 4-\frac{{8\times 4}}{{2\times 6}}+\frac{9}{8}

\displaystyle 4-\frac{{32}}{{12}}+\frac{9}{8}

\displaystyle 4-\frac{{4\times 8}}{{4\times 3}}+\frac{9}{8}

\displaystyle 4-\frac{8}{3}+\frac{9}{8}

\displaystyle \frac{4}{1}-\frac{8}{3}+\frac{9}{8}

\displaystyle \frac{{4\times 3}}{{1\times 3}}-\frac{8}{3}+\frac{9}{8}

\displaystyle \frac{{12}}{3}-\frac{8}{3}+\frac{9}{8}

\displaystyle \frac{{12-8}}{3}+\frac{9}{8}

\displaystyle \frac{{4\times 8}}{{3\times 8}}+\frac{{9\times 3}}{{8\times 3}}

\displaystyle \frac{{32}}{{24}}+\frac{{9\times 3}}{{8\times 3}}

\displaystyle \frac{{32}}{{24}}+\frac{{27}}{{24}}

If the denominators of all the different terms are equal,

then their numerators are added together.

so,

\displaystyle \frac{{32+27}}{{24}}

\displaystyle \frac{{59}}{{24}}