# How to solve 4{23+2-(1*2/3+4/3)5}1/2

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## How to solve 4{23+2-(1*2/3+4/3)5}1/2

We will solve this question in the following way in a simple way by writing it like this,

\displaystyle 4\left[ {23+2-\left( {1\times \frac{2}{3}+\frac{4}{3}} \right)5} \right]\frac{1}{2}

\displaystyle 4\left[ {23+2-\left( {\frac{2}{3}+\frac{4}{3}} \right)5} \right]\frac{1}{2}

\displaystyle 4\left[ {23+2-\left( {\frac{{2+4}}{3}} \right)5} \right]\frac{1}{2}

\displaystyle 4\left[ {23+2-\left( {\frac{6}{3}} \right)5} \right]\frac{1}{2}

\displaystyle 4\left[ {23+2-\left( 2 \right)5} \right]\frac{1}{2}

\displaystyle 4\left[ {23+2-10} \right]\frac{1}{2}

\displaystyle 4\left[ {25-10} \right]\frac{1}{2}

\displaystyle 4\times 15\times \frac{1}{2}

\displaystyle \frac{{4\times 15}}{2}

\displaystyle \frac{{\cancel{2}\times 2\times 15}}{{\cancel{2}}}

\displaystyle 2\times 15