# How to solve 45/9+27/15=6x/21

Welcome to my article How to solve 45/9+27/15=6x/21. This question is taken from the simplification lesson.
The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
For complete information on how to solve this question How to solve 45/9+27/15=6x/21 read and understand it carefully till the end.

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## How to solve 45/9+27/15=6x/21

Let us first write this question in this way,

\displaystyle \frac{{45}}{9}+\frac{{27}}{{15}}=\frac{{6x}}{{21}}

\displaystyle \frac{{5\times 9}}{{1\times 9}}+\frac{{3\times 9}}{{3\times 5}}=\frac{{2x\times 3}}{{9\times 3}}

\displaystyle \frac{5}{1}+\frac{9}{5}=\frac{{2x}}{9}

\displaystyle \frac{{5\times 5}}{{1\times 5}}+\frac{9}{5}=\frac{{2x}}{9}

\displaystyle \frac{{25}}{5}+\frac{9}{5}=\frac{{2x}}{9}

\displaystyle \frac{{25+9}}{5}=\frac{{2x}}{9}

\displaystyle \frac{{34}}{5}=\frac{{2x}}{9}

\displaystyle \frac{{34}}{5}-\frac{{2x}}{9}=0

\displaystyle \frac{{34\times 9}}{{5\times 9}}-\frac{{2x}}{9}=0

\displaystyle \frac{{306}}{{45}}-\frac{{2x\times 5}}{{9\times 5}}=0

\displaystyle \frac{{306}}{{45}}-\frac{{10x}}{{45}}=0

\displaystyle \frac{{306-10x}}{{45}}=0

\displaystyle 306-10x=0\times 45

\displaystyle 306=10x

\displaystyle \frac{{306}}{{10}}=x

\displaystyle 30.6=x

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