# How to solve 4+6/2+7/4=x-3+1/2

Welcome to my article How to solve 4+6/2+7/4=x-3+1/2. This question is taken from the simplification lesson.
The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
For complete information on how to solve this question How to solve 4+6/2+7/4=x-3+1/2, read and understand it carefully till the end.

Let us know how to solve this question How to solve 4+6/2+7/4=x-3+1/2

First write the question on the page of the notebook.

## How to solve 4+6/2+7/4=x-3+1/2

First of all write like this,

\displaystyle \text{ 4+}\frac{6}{2}\text{+}\frac{7}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ 4+}\frac{{2\times 3}}{{2\times 1}}\text{+}\frac{7}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ 4+}\frac{3}{1}\text{+}\frac{7}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ 4+3+}\frac{7}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ 7+}\frac{7}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ }\frac{7}{1}\text{+}\frac{7}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ }\frac{{7\times 4}}{{1\times 4}}\text{+}\frac{7}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ }\frac{{28}}{4}\text{+}\frac{7}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ }\frac{{28+7}}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ }\frac{{35}}{4}\text{=x-3+}\frac{1}{2}

\displaystyle \text{ }\frac{{35}}{4}-\frac{1}{2}\text{=x-3}

\displaystyle \text{ }\frac{{35}}{4}-\frac{{1\times 2}}{{2\times 2}}\text{=x-3}

\displaystyle \text{ }\frac{{35}}{4}-\frac{2}{4}\text{=x-3}

\displaystyle \text{ }\frac{{35-2}}{4}\text{=x-3}

\displaystyle \text{ }\frac{{33}}{4}\text{=x-3}

\displaystyle \text{ }\frac{{33}}{4}\text{+3=x}

\displaystyle \text{ }\frac{{33}}{4}\text{+}\frac{{3\times 4}}{{1\times 4}}\text{=x}

\displaystyle \text{ }\frac{{33}}{4}\text{+}\frac{{12}}{4}\text{=x}

\displaystyle \text{ }\frac{{33+12}}{4}\text{=x}

\displaystyle \text{ }\frac{{45}}{4}\text{=x}

\displaystyle \text{ 11}\frac{1}{4}\text{=x}

\displaystyle \text{x= 11}\frac{1}{4} [Answer]

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