# How to solve 9+3/2+8-6/3

Welcome to my article How to solve 9+3/2+8-6/3 , This question is taken from the simplification lesson.
The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
For complete information on how to solve this question 9+3/2+8-6/3, read and understand it carefully till the end.

Let us know how to solve this question 9+3/2+8-6/3

First write the question on the page of the notebook.

## How to solve 9+3/2+8-6/3

Let’s write this question first like this.

\displaystyle \Rightarrow \mathbf{9}+\frac{3}{2}+\mathbf{8}-\frac{6}{3}

\displaystyle \Rightarrow \mathbf{9}+\frac{3}{2}+\mathbf{8}-\frac{{2\times 3}}{{1\times 3}}

\displaystyle \Rightarrow \mathbf{9}+\frac{3}{2}+\mathbf{8}-\frac{2}{1}

\displaystyle \Rightarrow \frac{\mathbf{9}}{1}+\frac{3}{2}+\frac{\mathbf{8}}{1}-\frac{2}{1}

\displaystyle \Rightarrow \frac{{\mathbf{9}\times 2}}{{1\times 2}}+\frac{3}{2}+\frac{\mathbf{8}}{1}-\frac{2}{1}

\displaystyle \Rightarrow \frac{{\mathbf{9}\times 2}}{{1\times 2}}+\frac{3}{2}+\frac{{\mathbf{8}\times 2}}{{1\times 2}}-\frac{2}{1}

\displaystyle \Rightarrow \frac{{\mathbf{9}\times 2}}{{1\times 2}}+\frac{3}{2}+\frac{{\mathbf{8}\times 2}}{{1\times 2}}-\frac{{2\times 2}}{{1\times 2}}

\displaystyle \Rightarrow \frac{{18}}{2}+\frac{3}{2}+\frac{{16}}{2}-\frac{4}{2}

If the denominators of all the different terms are equal,

then their numerators are added together.

so,

\displaystyle \Rightarrow \frac{{18+3}}{2}+\frac{{16}}{2}-\frac{4}{2}

\displaystyle \Rightarrow \frac{{18+3+16}}{2}-\frac{4}{2}

\displaystyle \Rightarrow \frac{{21+16}}{2}-\frac{4}{2}

\displaystyle \Rightarrow \frac{{37}}{2}-\frac{4}{2}

\displaystyle \Rightarrow \frac{{37-4}}{2}

\displaystyle \Rightarrow \frac{{33}}{2}

\displaystyle \Rightarrow 16\frac{1}{2}

or,