Welcome to my article **How to solve; Factorise a^2(b+c) + b^2(c+a)+c^2(a+b)+2abc ?** This question is taken from the simplification lesson.

The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.

For complete information on how to solve this question **How to solve; Factorise a^2(b+c) + b^2(c+a)+c^2(a+b)+2abc ?**read and understand it carefully till the end.

Let us know how to solve this question **How to solve; Factorise a^2(b+c) + b^2(c+a)+c^2(a+b)+2abc ?**

First write the question on the page of the notebook

**How to solve; Factorise a^2(b+c) + b^2(c+a)+c^2(a+b)+2abc ?**

When we write it like this,

\displaystyle {{a}^{2}}(b+c)+{{b}^{2}}(c+a)+{{c}^{2}}(a+b)+2abc \displaystyle {{a}^{2}}b+{{a}^{2}}c+{{b}^{2}}c+{{b}^{2}}a+{{c}^{2}}a+{{c}^{2}}b+2abc \displaystyle {{b}^{2}}a+{{c}^{2}}a+2abc+{{a}^{2}}b+{{a}^{2}}c+{{b}^{2}}c+{{c}^{2}}b \displaystyle a({{b}^{2}}+{{c}^{2}}+2bc)+{{a}^{2}}b+{{a}^{2}}c+{{b}^{2}}c+{{c}^{2}}bwe know that ,

** \displaystyle {{(A+B)}^{2}}={{A}^{2}}+{{B}^{2}}+2AB**

so,

\displaystyle a{{(b+c)}^{2}}+{{a}^{2}}b+{{a}^{2}}c+{{b}^{2}}c+{{c}^{2}}b \displaystyle a{{(b+c)}^{2}}+{{a}^{2}}(b+c)+bc(b+c) \displaystyle a(b+c)(b+c)+{{a}^{2}}(b+c)+bc(b+c) \displaystyle (b+c)[a(b+c)+{{a}^{2}}+bc] \displaystyle (b+c)[ab+ac+{{a}^{2}}+bc] \displaystyle (b+c)[ab+bc+ac+{{a}^{2}}] \displaystyle (b+c)[b(a+c)+a(c+a)] \displaystyle (b+c)[b(a+c)+a(a+c)]** \displaystyle (b+c)[(a+c)(a+b)] (Answer)**

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