# How to solve (m^3-m+1)^2+(m^2-3)^2-2(m^2-3)(m^3-m+1)

Welcome to my article How to solve (m^3-m+1)^2+(m^2-3)^2-2(m^2-3)(m^3-m+1). This question is taken from the simplification lesson.
The solution of this question has been explained in a very simple way by a well-known teacher by doing addition, subtraction, and fractions.
For complete information on how to solve this question How to solve (m^3-m+1)^2+(m^2-3)^2-2(m^2-3)(m^3-m+1), read and understand it carefully till the end.

Let us know how to solve this question How to solve (m^3-m+1)^2+(m^2-3)^2-2(m^2-3)(m^3-m+1).

First write the question on the page of the notebook.

## How to solve (m^3-m+1)^2+(m^2-3)^2-2(m^2-3)(m^3-m+1)

To solve this question, we will write this question in the simplest form as follows and simplify it.

\displaystyle {{({{m}^{3}}-m+1)}^{2}}+{{({{m}^{2}}-3)}^{2}}-2({{m}^{2}}-3)({{m}^{3}}-m+1)

\displaystyle \Rightarrow \because {{a}^{2}}+{{b}^{2}}-2ab={{\left( {a-b} \right)}^{2}}

here,

\displaystyle a={{({{m}^{3}}-m+1)}}

\displaystyle b=({{m}^{2}}-3)

so,

\displaystyle \Rightarrow {{\left( {({{m}^{3}}-m+1)-({{m}^{2}}-3)} \right)}^{2}}

\displaystyle \Rightarrow {{\left( {{{m}^{3}}-m+1-{{m}^{2}}+3} \right)}^{2}}

\displaystyle \Rightarrow {{\left( {{{m}^{3}}-{{m}^{2}}-m+1+3} \right)}^{2}}

\displaystyle \Rightarrow {{\left( {{{m}^{3}}-{{m}^{2}}-m+4} \right)}^{2}}

\displaystyle \Rightarrow \left( {{{m}^{{3\times 2}}}-{{m}^{{2\times 2}}}-{{m}^{2}}+{{4}^{2}}} \right)

\displaystyle \Rightarrow \left( {{{m}^{6}}-{{m}^{4}}-{{m}^{2}}+16} \right) [Answer]

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