How to solve x(x+1)(x+2)(x+3)÷x(x+1)

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Welcome to my articlex(x+1)(x+2)(x+3)÷x(x+1)
This article has been taken from the simplification lesson, in this article we have been told to simplify with the action of addition, subtraction, multiplication, division and fractions.
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x(x+1)(x+2)(x+3)÷x(x+1)

Let’s solve it by putting it like this,

\displaystyle x(x+1)(x+2)(x+3)=x(x+1)

Taking x (x + 1) common to both the sides,

\displaystyle x(x+1){(x+2)(x+3)}=x(x+1){1}

Normally taken posts are removed from both sides,

\displaystyle {(x+2)(x+3)}={1}

\displaystyle (x+2)(x+3)=1

Now in this question,
If ,(x +2 )=1
So ,
x =1-2

x=-1 answer
And
If ,
(x +3 )=1
So ,
x =-2 answer

This article x(x+1)(x+2)(x+3)÷x(x+1) has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.

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HOW TO SLOVE x(x+5)(x+6)(x+2)÷x(x+5)(x+2) ?

First of all we should write the article on the page of the notebook.

x(x+5)(x+6)(x+2)÷x(x+5)(x+2)

Let’s solve it by putting it like this,

\displaystyle x(x+5)(x+6)(x+2)=x(x+5)(x+2)

Taking x (x + 5)(x+2) common to both the sides,

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\displaystyle {x\left( {x+5} \right)\left( {x+2} \right)}\left( {x+6} \right)=x\left( {x+5} \right)\left( {x+2} \right){1}

Normally taken posts are removed from both sides,

\displaystyle x+6=1

Now in this question,
If ,(x +6 )=1
So ,
x =-5 answer

How to solve x(x+1)(x+2)(x+3)÷x(x+1) This article x(x+5)(x+6)(x+2)÷x(x+5)(x+2) has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.

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See other similar examples (2)

x(x+1/3)(x+2/5)(x+5/2)÷x(x+1/3)(x+5/2)

First of all we should write the article on the page of the notebook.

x(x+1/3)(x+2/5)(x+5/2)÷x(x+1/3)(x+5/2)

Let’s solve it by putting it like this,

\displaystyle x\left( {x+\frac{1}{3}} \right)\left( {x+\frac{2}{5}} \right)\left( {x+\frac{5}{2}} \right)=x\left( {x+\frac{1}{3}} \right)\left( {x+\frac{5}{2}} \right)

Taking x (x + 1/3)(x+5/2) common to both the sides,

\displaystyle {x\left( {x+\frac{1}{3}} \right)\left( {x+\frac{5}{2}} \right)}\left( {x+\frac{2}{5}} \right)={x\left( {x+\frac{1}{3}} \right)\left( {x+\frac{5}{2}} \right)}(1)

Normally taken posts are removed from both sides,

\displaystyle \left( {x+\frac{2}{5}} \right)=(1)

\displaystyle x+\frac{2}{5}=1

Now in this question,
If ,(x +2/5 )=1
So ,
\displaystyle x=1-\frac{2}{5}

\displaystyle x=\frac{{5-2}}{5}

\displaystyle x=\frac{3}{5}Answer

How to solve x(x+1)(x+2)(x+3)÷x(x+1) This article x(x+1/3)(x+2/5)(x+5/2)÷x(x+1/3)(x+5/2)has been completely solved by tireless effort from our side, still if any error remains in it then definitely write us your opinion in the comment box. If you like or understand the methods of solving all the questions in this article, then send it to your friends who are in need.

See also  How to solve : 1+25/9+13/7+x=0

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